CPhill

(1.2 x 10 ^-16) / (9.11 x 10^31) =

(1.2 / 9.11) x (10^-48) ≈

.1317 x 10^-48 ≈

1.317 x 10^-49  (in scientific notation)

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Edit.....answer is 1.317 x 10^-48

Thanks for pointing out my mistake, ND !!!

We could also convert 13% to a decimal = .13

So

.13 * 200 = 26.00 = 26

Let x be the total cost of the jeans

And since the shopkeeper paid $3836 more for the shirts than the jeans, we have

x + x + 3836 = 9380

$2772 = x = total cost of the jeans

2772 + 3836 = $6608 = total cost of shirts

 Let y = number of jeans bought

Let p + 40 = price of one pair of jeans

Let 4y = number of shirts bought

Let p = price of each shirt

So we have that the price of a pair of jeans times the number he bought  = $2772.. or...

(p + 40)y = 2772

And, solving for y, we have

y = 2772/(p + 40)     

And the price of each shirt times the number he bought = $6608...or.....

p(4y) =  6608

And substituting in for y and solving for p, we have

4p[2772/(p + 40)] = 6608     (multiply both sides by p + 40 )

11088p = 6608p + 264320

4480p = 264320

p = $59  =  cost of each shirt

p + 40 = $99   =  cost of a pair of jeans

Now, to find the number of pairs of jeans bought, we have, the price of each pair times the number purchased = $2772....or......

$99y = $2772     solve for y

y = 28  = number of pairs of jeans bought

And he bought 4 times as many shirts, so... 4y = 4(28) = 112 = number of shirts bought

Verifying our answers

28($99) + 112($59) = $9380 = the total cost

So....$99 for each pair of jeans seems correct....

Hint....m<ACD  = 1/2 of its intercepted arc - since it's an inscribed angle.

And the arc that it intercepts is minor arc AD.

Does that help??

(The fact that AB and CD are parallel would only be useful info if we were trying to find m<BAC)

WolframAlpha gets a slightly different result from Melody's answer...I suspect the reason is in the way that WA is interpreting the multiple divisions of the two functions outside the brackets....

(The only change I made to the original problem was to subtract .2336 from both sides....)

Whatever.....I think the point here is that this one would be a tough one to evaluate by hand.......Based on the original form of the problem, it would be difficult to intuit how many "real' and/or "non-real" solutions there might be......

So we have triangle ABC with AB = 45, AC = 38, and an included angle BAC = (90 - 62) = 28°

And we're looking for BC. We can use the Law of Cosines for this.

BC² = AB² + AC² - 2(AB)(AC)cos28°

BC² = (45)² + (38)² - 2(45)(38)cos28°

BC² = 449.31923242222   ...and taking the square root, we have

BC ≈ 21.2 km

Let's divide and see..

17 1/2 = 35/2

So

(35/2) / (1/6) =

(35/2) * (6/1) =

35 * 3  =

105

And that's the answer

The geometric mean is defined as the nth root of the product of n numbers.......

So we have

  ⁵√(110*50*80*120*90) =  ⁵√(4,752,000,000) ≈ 86.17

We all give you "blue,"  rosala.......glad you feel better...nothing worse than being in bed and feeling bad!!

I love the last picure... I had a Chemistry teacher like that, once.....a really nice lady, but "lunch" time didn't mean a thing to her. She even used to keep talking after the bell to change classes rang!!!

159= -x -4(-7x -6)   distribute the -4 across both terms in the parentheses..we have

159 =-x +28x +24   subtract 24 from both sides and simplify

135 = 27x    divide by 27 on both sides

5 = x