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 #1
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x and y are similar shapes. the total surface area of x is 900cm squared. the total surface area of y is 1600cm squared. the volume of x is 540cm squared. calculate the volume of y

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(I'm going to assume that you meant the volume of x to be 540cm.3 )

Let's assume that we could take all the "surfaces" of x and lay them flat on a table.

Note that, if x's surface area is 900cm2, and it volume is 540cm3, the other dimension must be .6cm.

And the "scaling" factor  between the larger object y and the smaller similar object x is given by SQRT(y's surface area/ x's surface area) = SQRT(1600/900) = 40/30 = 4/3

To see that this is true, let's suppose that the surface area of x is just a square with a side = 30cm - it may not be a square, but let's suppose that it is !!  Again, let's suppose that the surface area of y is a square, too, with a side of 40cm. Then, the scaling factor is 4/3....for each dimension of x, the same dimension in y is 4/3 as long......since they're "similar" objects.

Well, if that's true, the other dimension of our hypothetical y must be = (4/3) * .6cm = .8cm.

So , if we could take y's "surfaces" and lay them flat, too, it's total volume would be !600cm * .8cm. = 1280cm3

Finally, no matter what the dimensions of x, each dimension of y is (4/3) as much. So, if the width (w) * length (l) * height (h) of x = volume = 540cm3, then the dimensions of y = (w*4/3) (l*4/3) (h*4/3) = (w* l * h)  * (4/3)3 =

(volume of x) * (scaling factor)3 = (540cm3) * (4/3)3 = 1280cm3.......which is just what we thought!!!

 

27 Apr 2014