Sorry......you mean everyone doesn't understand the language as I do ??     (LOL!!!)

Actually...I translated it using a Croatian-to-English app.

But if you tell me it's Slovak....I couldn't call you on it!!!

What is y=-3 graphed?

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It's just a line parallel to the x-axis that passes through the y-intercept of 3 -  the point (0,3).

All points on its graph have a y coordinate =3, no matter what their x coordinates. Also, this line has a slope = 0.

The data set I have is 14.2, 15.6, 16.3, 17.1, 17.9, 18.6, 20.0

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Let's see how much of statistics I remember!!

First, let's find the mean (average) of this data set. We just sum the numbers and divide by the number of them that we have, (7)........

This gives:   ( 14.2+ 15.6 +16.3 + 17.1 +17.9 + 18.6 + 20.0 ) / 7   = 17.1

The, we subtract each of the values from the mean and square the result....note that we can disregard 17.1 itself !! (Subtracting it from the mean = 0)

So we have

(17.1 - 14.2)² = (2.9)²  = 8.41

(17.1 - 15.6)² = (1.5)²  = 2.25

(17.1 - 16.3)² = (.8)²    =   .64

(17.1 - 17.9)² = (-.8)²   =   .64

(17.1 - 18.6)² = (-1.1)²  = 1.21

(17.1 - 20.0)² = (2.9)²  =  8.41

Now, sum the values on the right hand side

We have (8.41 + 2.25 + .64 + .64 + 1.21 + 8.41) = 21.56

Now, since this is a "sample," we need to divide this by (the number of values - 1) = (7-1) = (6)

This gives us (21.56/6) ≈ 3.59

Now, take the square root of this   SQRT(21.56/6) = 1.895

And, assuming I didn't make any math errors, that's the standard deviation ... (S.D.)

Now....you might have the same question that I had when I first saw S.D......So what???

Well....what this tells us is how far (on average) each score is from the mean.  A "high" S.D. indicates a "dispersed" data set and a "low" S.D. indicates a data set that is bunched closely around the mean. This data set seems to be fairly closely bunched around the mean.......we don't have any "large" outlier values that would tend to "skew" the S.D. very much. Of course, the terms "high," low" and "closely bunched" are all relative to the situation.

Note....because this process is lengthy, it's usually better to use some sort of application to find S.D.

Here's an app to help you with that:

write a system of equations with the solution (4,-3)

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OK....this isn't so tough to do..... we only need two equations!!

One equation could be

5x - 2y = 26

The other could be

1x - 1y =   7

For reasons I won't go into, I know there is a unique solution to this. And our unique solution is (4, -3).

Check this for yourself/  Also.......this isn't the "only" system that "works." (We could have an infinite number of them!!)

Cos(A-B), SinA=3/5 SinB=5/13

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Cos (A-B) = CosACosB + SinASinB

Since we're dealing with "Pythagorean Triples" triangles, CosA = 4/5 and CosB = 12/13

So we have.....(4/5)(12/13) + (3/5)(5/13) =  48/65 + 15/65 = 63/65

2/3[(5+3)^2-31]

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OK.....let's simplify things a bit   we have

(2/3) [8² -31]

(2/3) [64 - 31]

(2/3)[33]

66/3

22

is 1/3 15/27

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Here's a method to determine whether two fractions are equal.......just cross-multiply.....if the products are equal, then the fractions are equal!!

So........1x27 = 27       3 x 15 = 45    Nope!!!

"Reducing"  15/27 gives us 5/9 !!

By the way.....look at these fractions closely.....isn't 15 more than 1/2 of 27???   So there's no way that 15/27 = 1/3, as we can determine just by examination....

Re: Kako se racuna zapremina?

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Budi precizniji ...... volumen kakav predmet (ili oblik?)

(Be more specific......the volume of what object (or shape??))

if julie runs seven miles each day except for sundays, how many miles will she have ran in three months?

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Well....depending on the months, let's just say that a three month period lasts 90 days.

Let's let her begin running on a Monday.

Note that 90 days = (13 weeks - 1 day).

So she runs 13 weeks x 6 days per week x 7 miles per day = 13 x 42 = 546 miles.

Notice, that in the last week, Sunday would be the 91st day....but she doesn't run on that day, anyway.

what is the nth rule for this sequence/ 4,10,16,22?

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a_n = 4 + 6(n-1)   = 6n - 2   where "n" is the n^th term