From the package, we can choose any 4 of the 10. Thus, we have C(10,4) =210 ways of choosing the wheels.
But this only answers part of the question. On the skates themselves, we have 4 ways to choose which wheel goes on first, 3 ways of choosing the next one to go on, 2 ways for the next, and 1 way for the last.
So, the total number of ways to fit the wheels to a skate are 4 x 3 x 2 x 1 = 24.
So, the total ways to select the wheels from the package, times the number of ways to fit them to a skate = 210 x 24 = 5040.
I think this is correct, but I'd like someone to "check" me!!