CPhill

So we have this equation:

n² - 10 = 3n    Rearranging, we have

n² - 3n - 10 = 0   Factoring, we have

(n-5) (n+2) = 0  setting each factor to 0 and solving

n = 5  n= -2

Note that both numbers "work" for the problem.

(5x)/3 + 15/2  = 5/2

Well....we could multiply through by a common denominator...but here's something easier...just subtract the 15/2 from both sides...we get

(5x)/3 = 5/2 - 15/2

(5x)/3 = -10/2

(5x)/3 = -5   Now multiply both sides by 3

5x = -15       Divide by 5

x = -3

1 - (1/4) - (1/16) - (3/8) =

1 - (4/16) - (1/16) - (6/16) =

1 - (11/16) =

(5/16)

We both got the same result...now, let's figure the probability that 2 board members out of (n) board members could arrive at the same (possibly) correct answer!!

No snide remarks here, please.....

A rod is a measure used in surveying. It equals 16.5 feet. As I understand it, it's an easy unit to use when calculating acreage.

And that's as much as I know about it.....

Probabilty isn't my strong point, but I'll take a run at this one.

So, basically, we first want to count the sets of people who might die - what a morbid problem!!

The total number of people who could die is given by choosing some group of 4 from the 17 =  C(17,4) = 2380

Now, let's look at the possible sets where 1 skier dies. This is given by C(3,1)*C(13,3) = 858 sets

Now, let's look at the possible sets where 2 skiers die - C(3,2) *C(13,2) = 234 sets

Now let's consider the sets where all three skiers die = C(3,3) * C (13,1) = 13

So, the total number of sets containing any of the skiers = 1105

Thus, the chances that all three survive are given by:

1 - (the number of sets containing any of the skiers)/(the total number of possible sets)

=  1 - (858 + 234 + 13)/2380 ≈ 53.6 %

OOPS !!    Melody pointed out a math error  I made....let me correct this...and as she indicated recently, she DOES believe in "do-overs"....I still like my logic, though!

Now, let's look at the possible sets where 1 skier dies. This is given by C(3,1)*C(14,3) = 1092 sets

Now, let's look at the possible sets where 2 skiers die - C(3,2) *C(14,2) = 273 sets

Now let's consider the sets where all three skiers die = C(3,3) * C (14,1) = 14

So, the total number of sets containing any of the skiers = 1379

Thus, the chances that all three survive are given by:

1 - (the number of sets containing any of the skiers)/(the total number of possible sets)

==  1 - (1379)/2380 ≈ 42.1 %

Thanx, Melody!!

Sorry....I'm busy at the moment trying to extricate a Roman zero from a boulder........

It's a hyperbolic problem...........and that' s no hyperbole.....

"8 times the number that is less than x"

Did you leave something out here??

There might be many numbers that are "less than x."

This is what Anonymous is saying in a more compact manner

C = 2*pi*r    divide by 2*pi on both sides

C/(2*pi) = r

(Don't worry, Anonymous, I'll give you the "points, here!!)

√(27a⁷) = √27 * √(a⁷) = 

√9 * √3 * √(a²) *√(a²) *√(a²) *√(a) =

3√3 * a * a * a * √(a) =

3a³√(3a)