lol you can call it fast walking
Ok she drives distance of (120+150) miles in total in (2+1+3) hours trip total.
So we have \(\frac{(120+150)}{(2+1+3)}=\frac{270}{6}=45\)
Finally the average driving speed, in miles per hour, during her trip is:
45 miles/hour
Hope this helps!
Nice CPhill!
Yes you can do and this :
\(\frac{a^4}{3(3^2-a^2)}\)
\(\frac{\frac{a^2}{3^2}}{\frac{3^2-a^2}{3a^2}}=\frac{3a^2a^2}{3^23^2-3^2a^2}=\frac{a^4}{3^3-3a^2}\)
Yes tan= 15/8 it's between 61,62 degrees!
Welcome!
\(sin(x)=\frac{opposite }{hypotenuse }<=> sin(65)= \frac{15 ft}{d} <=> d= \frac{15}{0,906}\)
d~16,556 ft
\(\frac{banana tree}{mangotree}=\frac{2}{3} <=> \frac{2.5}{mangotree}=\frac{2}{3} <=> mangotree=\frac{2.5\times3}{2}=\frac{7.5}{2}=3.75m\)
So mango tree is 3.7m tall!
