Melody

Yes - you did. 

And

"That is what I thought!"  is not 'thank you.'

Hey Freddie,

What happened to

"If you can tell me what I did wrong, I will like all your stuff for a week!"

I do not see any 'likes' on EP'S answer, and he was directly helping you!

Have a play with this graph and see if you can work it out.

Thanks Rom, I just want to see if i can do this myself :)

Pat wants to select 8 pieces of fruit to bring in the car for the people he's driving to Montana with. He randomly chooses each piece of fruit to be an orange, an apple, or a banana. What is the probability that either exactly 3 of the pieces of fruit are oranges or exactly 6 of the pieces of fruit are apples?

I am going to assume that it is ok to have exactly 3 oranges AND exactly 6 apples 

     .... Nope that is impossible since there are only 8 peices of fruit.

8 peices of fruit

I am going to have  the apples first, then the bananas and last the oranges

I'l use stars and bars too.

8 stars   2 bars

total number of possibilities is   10C2 = 45

number of combinations if there are exactly 3 oranges    OOO|    1 2 3 4 5 6        6C1= 6

number of combinations if there are exactly 6 apples        1 2 3 | a a a a a a a     3C1= 3

So I think that the answer is    

P(exactly 3 oranges or exactly 6 apples) = 9/45  = 1/5

I got the same as you ROM. 

That doubles the chance that it is correct   

Nice answer Max :)

Yes I have a lot of fun using Geogebra too. 

I am still finding new functions in there. It can really do a lot of things. 

For anyone that is interested,it is a free download.

The ansswer was wrong then.

I answered this one a short time ago.

Lets see.

7*5! = 840 that takes care of rotation

There are 6 axes of symmetry so I think that should be divided by 6

7*5!/6 = 140

420 is definitely NOT correct. 

140 might be correct.

Nice pic Chris :)

Hi aNotSoSmartPerson

I just did that.

But you are right I added one that was too big.

There are 11   - just like you said