Melody

5 musicians, all together, 5! ways if each scientist is considered an individual

2 scientists, all together,  2 ways if classed as individuals

1 accountant

2*5!*2 = 4*5! = 480 ways

Note:

If you say it is wrong without giving your reason then your response will be whited the same as your other rude responses have been whited.

It is never stupid to ask a genuine question.  However, if you do not understand then it would be stupid to not ask.   

\(x^{-y}=\frac{1}{x^y}\\ p^{-2}=\frac{1}{p^2}\\ etc\\ \text{that is what a negative power means}\\ so\\ (\frac{1}{3})^{3/5}\\ =(\frac{1}{3})^{0.6}\\ =\frac{1}{3^{0.6}}\\ =3^{-0.6}\)

--------------------

Think about how index laws work

\(x^3\div x^7=x^{3-7}=x^{-4}\\ but\\ x^3\div x^7=\frac{x^3}{x^7}=\frac{xxx}{xxxxxxx}=\frac{1}{x^4}\\ therefore\\ x^{-4}=\frac{1}{x^4}\\\)

By the way, your post was blanked out because you used the word 'stupid'

It was blanked out for me too but I have the power to unblank  

Barry has 4 wooden blocks, 2 are blue, 1 is red and 1 is green. How many ways can he arrange the 4 blocks in a line?

4!/2!=12 ways

Barry's friend Billie is colour blind and cannot distinguish between red and green. How many ways can the blocks be arranged so that Billie can see different looks?

4!/2!2! = 6 ways

\(R=p*T^q\\ \)
\(T=3R^{(5/3)}\\ \frac{T}{3}=R^{(5/3)}\\ (\frac{T}{3})^{(3/5)}=R\\ R=(\frac{T}{3})^{(3/5)}\\ R=(\frac{1}{3})^{(3/5)}*T^{(3/5)} \\~\\ p=(\frac{1}{3})^{(3/5)}\\ p=3^{(-0.6)}\\ p\approx 0.517\\~\\ p\approx 0.5\qquad(1\;dec\;place)\\ q=3/5=0.6\qquad (exact) \)

ok thanks Alan.

thanks for the note:) 

(127)^4−x     =    9^2x−1

should be written as

127^(4−x)     =    9^(2x−1)

Looking for real solutions.

\(127^{4−x}     =    9^{2x−1}\\ log(127^{4−x} )    =    log(9^{2x−1})\\ (4-x)log(127 )    =    (2x-1)log(9)\\ 4log127+log9 = 2xlog9+xlog127\\ 4log127+log9 = x(2log9+log127)\\ x=\frac{4log127+log9}{2log9+log127} \\ \)

x is approximately 2.335

ok thanks Alan.

Hi guest,

I looked here....... but how do you know for sure that they are all irrational ?

I just had fun drawing this curve

\(y=a(x^4-8x^3+8x^2+52x-77)\)

In the case of this picture 'a' is negative

Ok, got it.  Thanks Alan