Melody

Hint

The circumference of a circle is  2pi*r   and a circle has  360 degrees 

so

length of an arc  =    \(\frac{\text{angle in degrees} }{360}*radius.\)

That is enough of a hint, if you want to interact with me (or whichever answerer that is around) that would be good.

Is dp1806's Latex displaying properly for you ilorty?

I know there are some display problems for some people but I think that is just a problem for guests.

I think dp1806 is just copying and posting unrendered Latex because he is too lazy to attempt to present it properly.

I have asked dp1806 about this personally and he has not attempted to defend himself.

If you think I am wrong then please say so.

That is ok Jenny. I am not terribly comfortable with limits myself.

If you do not understand it is quite reasonable for you to ask again.

So long as you do the best you can,to get as much as possible, from already provided answers, more questions are fine.

Thanks for showing me that.

Your souce is right.

I have double counted.

For the last 3 cards I have counted  order where I should not have.

I mean I have counted 345 separately from 354 etc.  where they are both the same.

I could have fixed this by dividing my answer by 3! = 6

6 300 000/6 = 1050000      And now the answers are the same    

ok, I did not think about the question properly.

let alpha be a very small positive number

if x=1+alpha  then  1/(x-1)  is a positive huge number.

tan of a positive huge number 

if x=1-alpha  then 1/(x-1)  is a negative equally huge number.

tan of a positive huge number is not equal to tan of a negative equally huge number.

So yes I suppose it is reasonable to conclude that the function is not continuous at x=1.

I am posting this on behalf of Nacirema.  I have not tried it myself.

Copied from a private message:

"Sorry, it will not let me post. Can you post this on my behalf please:"

I have a fairly nifty trick which I use to upload the screenshots when the image file does not pull up. In fact, this works with almost any image I try to upload to https://web2.0calc.com! Please read to the end, I do not want you to do it the hard way.

Step 1: Create a second email. 

Step 2: Go to http://hangouts.google.com.              I know this sounds irrelevant, but trust me it works. 

Step 3: Feed in the email address to the (+Add Contact) option. 

Step 4: Go to http://hangouts.google.com on the new email address.

Step 5: Go to invites and accept the invitation.

Step 6: Upload the image that you want to paste onto http://web2.0calc.com.

Step 7: Once it has sent, click on the image. It will open a new tab.

Step 8: Copy the URL Code and come back here. 

Step 9: Click on the image option and paste the URL Code into the URL Code slot. It ought to have uploaded by this time. You are done. Once this is done, and each time you want to upload a new image, repeat from Step 6, not Step 1. This saves significant time.

Nacirema

I do not think the first one can be determined using limits.  (It is undefined)

the second one is very straight forward  it is just e^0 and that has the defined value of 1.

any number to the power of 0 is 1

 e is just a special irrational number. Its value is approx 2.718

ilorty, 

Some of your links do not work at all and one goes to the wrong place. (For me anyway)

You need to check them.  

Thanks ilorty.

I think your knew news posts will be excellent.

Maybe we will all learn to spell too  

When reposting, please give the a link to the original question.

like this: