Melody

921 Questions
34315 Answers

-2

1730

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+118690

Mathigon website

I just discovered a site called mathigon

https://mathigon.org/dashboard
और पढ़ें ..

Melody 2 Apr 2022

-10

594

1

+118690

Reporting problems.

There are a number of people having problems at the moment.
If you lodge an error can you please give all relevant information that you can think of.
Where you are in the world - the city or the country - is often very important information. और पढ़ें ..

Melody 16 Mar 2022

-4

1402

5

+118690

How to make an empty rectangle in Latex

I just worked out how to make an empty box of various horizonal size easily in LaTex.
This is not a recommended method, but other methods that I have tried here have not worked.
This coding is really simple. Just put letters inside और पढ़ें ..

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Melody 15 Mar 2022

-5

857

3

+118690

HAPPY ANNIVERSARY CHRIS! (CPhill)

I just realized that you became a member here exactly 8 years ago today!

It has been great to have you here all that time

और पढ़ें ..

विषय से परेे

Melody 13 Mar 2022

-6

836

3

+118690

WELCOME BACK CPHILL !

Melody 11 Feb 2022

-6

707

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+118690

Very interesting question. No high level maths required.

This question was posted a couple of days ago.
https://web2.0calc.com/questions/geometry_73561

I think it is really interesting. It looks much more difficult than it really needs to be. और पढ़ें ..

Melody 1 Feb 2022

-8

869

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Members have a better experience. Their questions get more attention.

Almost everyone is posting as a guest.
If you post as a member your questions will have a far greater chance of a timely and helpful response.
If you are a genuine learner and interact with us, you will become known and answerers will do और पढ़ें ..

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Melody 9 Jan 2022

-8

1

980

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HAPPY BIRTHDAY CHRIS!

और पढ़ें ..

Melody 20 Des 2021

+4

1

5471

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+118690

Some guidelines for question askers.

Please note:
1) Ask only one question per post.
2) When asking a question talk about what you have tried for yourself. Then people will take you more seriously and will be more able and willing to help.
3) If you get an answer और पढ़ें ..

विषय से परेे

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Melody 4 Nov 2021

-10

1077

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+118690

Remeniscing - a little historical humour.

I just found this old post that some of you, who have been around for a while, might find amusing.

https://web2.0calc.com/questions/look-at-the-new-leader-board

विषय से परेे

Melody 29 Okt 2021

+118690

0

Find the smaller and bigger values of b in the function x^2+bx-29

b can be any number.
Maybe there is something missing from your question.

Melody27 Okt 2013

+118690

0

(8--3)(8^2+8*-3+-3^2)
but I think you may really have meant
(8--3)(8^2+8*-3+ (-3)^2)

=(8+3) * (64 +(8*-3) + (-3*-3))
=11 * (64 + -24 + +9)
=11* (64-24+9)
=11*49
=539

If you really did mean
(8--3)(8^2+8*-3+-3^2) then it will be
= 11*(64-24-9)
= 11*31
= 341

Melody27 Okt 2013

+118690

0

-4(2x - 1) = -6(x + 2) - 2

-4*(2x - 1) = -6*(x + 2) - 2

-4*2x - -4*1 = -6*x + -6*2 -2

-8x + 4 = -6x -12 -2

-8x + 4 = -6x -14

now add 6x to both sides
then subtract 4 from both sides
then divide both sides by the number in front of the x
then it will be finished.

Melody27 Okt 2013

+118690

0

A music publisher earns a 6.75% commission on the moey made from the use of a song on a CD. If the music publisher earns $84,375, how much money was made from the use of the song?

Let the money made be x dollars

0.75% of x = $84375

0.0075 * x = $84375

x = 84375 / 0.0075

x = 1.125 * 10 ⁷

x = $11,230,000

Melody27 Okt 2013

+118690

0

24.7% of $90.00.

=24.7 / 100 * 90.00

Melody27 Okt 2013

+118690

0

http://physics.mercer.edu/labs/manuals/manualMECHlab/errorAnalysisDensity/ErrorAnalysis.pdf

an aluminum block displaces a volume of 15.5ml water and has a mass of 40.5g. What is its density?
Why it Could be a little different from the theoretical value? (Theoretical density of aluminum is 2.70 g / cubic cm

density = mass/ volume
15.5ml of water takes up 15.5cm cubed

Experimental density = 40.5g / 15.5cm ³

=2.61 g/cm ³

Experiment values are never going to be identical to theoretical values.
For a start the answer can only be as accurate as the equipment you are using will allow.
The above web address looks at this type of error, if you are interested enough.

Melody27 Okt 2013

+118690

0

(y^2-6y+4)+(7y^2+5y+2)

= y^2-6y+4 +7y^2+5y+2

=8y^2 -6y+4 +5y+2

=8y^2 -1y +6

=8y^2 - y + 6

Melody27 Okt 2013

+118690

0

If a movie starts at 6:45pm, and is 103 minuets long, would I have time to catch a different movie at 7:25pm? What time would the 7:25pm movie end if its 117 minutes long?

103min = 60+43 min = 1hr 43 min
6 hrs and 45min + 1hr and 43 min = 7hr and 88min = 7hrs + 1hr and 28min = 8:28
the first movie finishes at 8:28pm

117min = 60+57 min = 3 minutes less than 2 hours = 2 hours - 3 min
7:25 + 2hours - 3min = 9:25 - 3min = 9:22pm
The second movie will finish at 9:22pm

Melody27 Okt 2013

+118690

0

Hi Rosey,
I can't help you unless you give me more information because this is Mexican tax (I assume it is anyway)
Every country has its own tax rates and tax rules. I'd have to have more information about it.
I don't know how your FIT tax is calculated or if it is the same for everyone. From the questions I am guessing that it is different for married people than for single people.
Anyway, I would like to help you but I can't unless you give me more information.
Sorry.

Hola Rosey,
No te puedo ayudar si no me das más información porque esto es impuesto mexicano (asumo que es de todos modos)
Cada país tiene sus propios impuestos y normas de impuestos. Tendría que tener más información sobre él.
No sé cómo se calcularon su ajuste de impuestos o si es el mismo para todos. De las preguntas me imagino que es diferente para gente casada que para personas solteras.
De todos modos, me gustaría ayudarte pero no puedo si no me das más información.
Lo siento.

Melody27 Okt 2013

+118690

0

(^3√5y^4)/(^3√15x^4) = [ 5^(1/3) * (x^4) ] / [ 15^(1/3) * (x^4) ]
Is this what you mean?
If so, then this is the answer

= [ 5^(1/3) * (x^4) ] / [ 15^(1/3) * (x^4) ]

= [ 5^(1/3) * (x^4) ] / [ 5^(1/3) * 3^(1/3) * (x^4) ]

= [ y^4 ] / [ 3^(1/3) * (x^4) ]

Melody27 Okt 2013