Melody

Excellent answer Dragon - You really are learning.  

I am very impressed!

Double thumbs up from me and Chris.

Now I want to see more really good post like this and a lot less others. 

Here is another LaTex pointer.

\\means start a new line, I usually use \\\\ because I like my lines to be well spaced.

So you could have written this without going in and out of LaTex lots of times.  

Hi Dragon Slayer,

I see you have found a new method for making 'legitimate' posts.  I hope that you learn something from it. 

Anyway, I have learned something - I have never written this in LaTex before!

By the way, LaTex is pronounced LayTec

$$\\\sum \quad
\mbox{This is the Greek letter 'capital sigma' and it means 'sum of'}\\\\
\sum\limits_{n=1}^5\;(n^2-1)\\\\
=(1^2-1)+(2^2-1)+(3^2-1)+(4^2-1)+(5^2-1)\\\\
=1+3+8+15+24\\\\
=51\\\\
\mbox{You see how I have replaced the n with the numbers from 1 to 5 and added them all together?}$$

Oh sorry, I didn't even notice the original question.  This was a puzzle question.

I think that Aziz answered it a day or 2 ago.  I think it was Aziz, maybe it was Ninja but I don't think so. 

It was a really good answer too.  

       CONGRATULATIONS ON YOUR STAR DRAGONSLAYER554!!!       

5 is the answer.

$${\mathtt{50}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{8.95}} = {\mathtt{\,-\,}}{\frac{{\mathtt{37}}}{{\mathtt{10}}}} = -{\mathtt{3.7}}$$

-3.70 pounds

$${\frac{{\mathtt{5\,664\,503}}}{{\mathtt{5}}}} = {\mathtt{1\,132\,900.6}}$$

That number does.

I know how to use Google.  Arn't I clever. 

Ok. Now I am going to give a much better more concise  answer.

The triangle on the top is similar to the full big triangle because they have two equal angles.  A common right angle and a common angle theta at the top.  Therefore their sides are in the same ratio therefore,

$$\begin{array}{rll}
\frac{y}{x}&=&\frac{6}{4.2}\\\\
y&=&\frac{6}{4.2}x\\\\
y&=&\frac{10}{7}x\\\\
\frac{dy}{dx}&=&\frac{10}{7}\\\\\\
\end{array}
\frac{dy}{dt}=\frac{dy}{dx}\times \frac{dx}{dt}\\\\
\frac{dy}{dt}=\frac{10}{7}\times 1 \qquad \mbox{We were given that }\frac{dx}{dt}=1\\\\
\frac{dy}{dt}=\frac{10}{7}$$

The end of the shadow is moving away from the light pole at a constant speed to 10/7 m/sec

The shadow is increasing in length at  constant rate of 3/7 m/s

Sat 2/8/13

A treason plot has been uncovered!