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ई - मेल से संपर्क करे
Melody
यूजर का नाम
Melody
स्कोर
118690
Membership
Stats
सवाल
900
जवाब
33647
921 Questions
34315 Answers
-2
1731
2
+118690
Mathigon website
I just discovered a site called mathigon
https://mathigon.org/dashboard
और पढ़ें ..
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Melody
2 Apr 2022
-10
595
1
+118690
Reporting problems.
There are a number of people having problems at the moment.
If you lodge an error can you please give all relevant information that you can think of.
Where you are in the world - the city or the country - is often very important information.
और पढ़ें ..
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Melody
16 Mar 2022
-4
1403
5
+118690
How to make an empty rectangle in Latex
I just worked out how to make an empty box of various horizonal size easily in LaTex.
This is not a recommended method, but other methods that I have tried here have not worked.
This coding is really simple. Just put letters inside
और पढ़ें ..
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Melody
15 Mar 2022
-5
858
3
+118690
HAPPY ANNIVERSARY CHRIS! (CPhill)
I just realized that you became a member here exactly 8 years ago today!
It has been great to have you here all that time
और पढ़ें ..
विषय से परेे
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Melody
13 Mar 2022
-6
836
3
+118690
WELCOME BACK CPHILL !
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Melody
11 Feb 2022
-6
707
2
+118690
Very interesting question. No high level maths required.
This question was posted a couple of days ago.
https://web2.0calc.com/questions/geometry_73561
I think it is really interesting. It looks much more difficult than it really needs to be.
और पढ़ें ..
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Melody
1 Feb 2022
-8
870
11
+118690
Members have a better experience. Their questions get more attention.
Almost everyone is posting as a guest.
If you post as a member your questions will have a far greater chance of a timely and helpful response.
If you are a genuine learner and interact with us, you will become known and answerers will do
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Melody
9 Jan 2022
-8
1
981
3
+118690
HAPPY BIRTHDAY CHRIS!
और पढ़ें ..
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Melody
20 Des 2021
+4
1
5471
9
+118690
Some guidelines for question askers.
Please note:
1) Ask only one question per post.
2) When asking a question talk about what you have tried for yourself. Then people will take you more seriously and will be more able and willing to help.
3) If you get an answer
और पढ़ें ..
विषय से परेे
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Melody
4 Nov 2021
-10
1077
1
+118690
Remeniscing - a little historical humour.
I just found this old post that some of you, who have been around for a while, might find amusing.
https://web2.0calc.com/questions/look-at-the-new-leader-board
विषय से परेे
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Melody
29 Okt 2021
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#1
+118690
0
simplify 7a/15b^2 + b/18ab
This is the question that you have asked, is it what you intended?
simplify [ (7a/15)*b^2] + (b/18) *ab
or did you really mean
simplify 7a/(15b^2) + b/(18ab)
or maybe you meant something else ??
Melody
18 Nov 2013
#2
+118690
0
sorry, this isn't correct.
Try to google it to find the correct answer
Also, it is the
surface area
of a sphere that you want.
Melody
18 Nov 2013
#1
+118690
0
Try working your way through a log unit
maybe
http://www.mathsisfun.com/algebra/logarithms.html
Melody
18 Nov 2013
#1
+118690
0
How much mixture do you want to make up altogether?
Melody
18 Nov 2013
#1
+118690
0
log(x) - (1/2)log(x+4) = 1
log(x) - log(x+4)
1/2
= 1
log[x/(x+4)
1/2
] = 1
Now I need to know what base it is in. I will assume base 10
x/(x+4)
1/2
= 10
etc
This will lead to a quadratic equation that you will have to solve.
You should work through a unit on logs maybe
http://www.mathsisfun.com/algebra/logarithms.html
Melody
18 Nov 2013
#1
+118690
0
((e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000))/e^(100x=Q What is Q?
I re-presented the question as follows - is this what the question was?
[ (e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000) ] /e^(100x)=Q What is Q?
Q = [ (e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000) ] /e^(100x)
Q = 100sin(x)- 120pi*cos(x)/(14400pi^2+10000)
Q = 1000[0.1sin(x)- [0.120pi/(14400pi^2+10000)]*cos(x)]
--------------------------------
Now using Sin(x-A)=sinx * cosA - sinA * cosx
let
cosA=0.1
sinA= 0.12pi/(14400pi^2+10000)
tanA=0.12pi/(14400pi^2+10000)/0.1 = 1.2pi/(14400pi^2+10000)
A = 2.47821*10^(-5) (to 6 sf)
-----------------------------------
Q = 1000*sin[ x - atan(1.2pi/(14400pi^2+10000))] exact if I didn't make a mistake
Q = 1000*sin[ x - 2.47821*10^(-5)] (this answer is not exact)
I think that's right but I could easily have made a mistake.
Melody
18 Nov 2013
#1
+118690
0
11/50 * 870 Litres
It is actually
11Litres/50Km * 870km but the km cancel out. (You can cancel units just the same as you can cancel numbers)
Melody
17 Nov 2013
#1
+118690
0
(1-sqrt(2))^2-1/(sqrt(2-1
Do you mean
(1-sqrt(2))^2- {1/(sqrt(2)} -1 ??
Melody
17 Nov 2013
#1
+118690
0
What help?
Melody
17 Nov 2013
#1
+118690
0
Draw the diagram
use pythagoras to ger the third side
Read the ratios off the diagram.
remmeber the word
soh cah toa
sin=o/h
cos=a/h
tan/o/a
or if you prefer, you can remember
Some old hags
Can't always hide
their old age
co
t
=1 /
t
an
co
s
ec=1 /
s
in
se
c
=1 /
c
os
I am trying to show you that the
first letter of original ratio = third letter of new one.
Melody
17 Nov 2013
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