$$y=(x+1)^2$$ is a concave up parabola. The root is x=-1 That is the only value that will make y=0
you want to know where y>0
Well it will be greater than zero everywhere except where x=-1
You should draw the parabola to help you understand why this is so.
Formal solution
$$x \in R \qquad where \quad x \ne-1$$
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