6
$$\\6x-2x*(3-x)\\\\ =6x-2x*3--2x*x\\\\ =6x-6x+2x^2\\\\ =2x^2\\\\$$
$$\\3.8*10^{27}\;*\; 3.1*10^7\\\\ =3.8*3.1*10^{34}\\\\ =11.78*10^{34}\\\\ =1.178*10^{35}\\\\$$
I didn't answer LOL, it was Alan and Chris. Thanks guys
To subtract a negative number is like taking away cold air - the room gets warmer.
so - - = +
cos 160 = -cos(180-160) = -cos20
Dragon you made a mistake!
It was your very fist MathWay question! the answer had a blue tick!
It doesn't have to be used with a variable - it will be true anyway
6(3+5)=6*(3+5)=6*3+6*5=18+30=48
I think we need more information.
It looks like chapter 4.