Melody

The main ones that we use is Desmos, it makes beautiful graphs but it does have limitations.

then we use wolfram|alpha

there are others that we pull out very occasionally.

I do not know what I could use for those graphs I drew for you this afternoon - that is why I drew them free hand.

@@ End of Day Wrap       Mon 29/9/14        Sydney, Australia      Time 11:15 pm      ♬  

Hi all,

Today our favulous answerers were NathanDeAlien, Quinn, CPhill, NinjaDevo, Geno3141, DragonSlayer554, Alan and Kitty<3.  Thank you all.    

The site is playing up tonight.  Pictures are not displaying properly and for some reason i couldn't give 
Alan points on one of his posts, sorry Alan.  Hopefully these problems won't last long.  

Now for the interest posts:

1) Do donkeys fly?  What a silly question.

the wording is rather strange but supplementary angles add to 180 degrees

so the angles are   104 and 180-104 degrees

Tues 29/9/14

1) Finding last digit

Thanks Geno,

I am just going to work through my version of your logic.  :)

$$\\x^{15}+x^5+2=0\\\\
Let\;\;y=x^5\\\\
y^3+y+2=0\\\\
y(y^2+1)=-2\\\\
y^2+1 $ must be positive so $y$ must be negative. Hence$\\\\
x^5$ must be negative, hence $\\\\
x $ must be negative$\\\\
$Therefore, no positive roots exist.$$$

Alan, I have tried to give you points for your last answer but the system is playing up and it will not allow it.

Sorry.    

$$8.6\times 10^3$$

Hi Alan,

I didn't understand the middle one partly because I didn't/don't understand what is happening.

I assume the glider is getting pulled up the slope with constant Force. 

Since force = mass  x  acceleration

The mass is constant so the acceleration is constant.  That makes sense, at least as far as the formula goes.

So even if the velocity is constant there is still acceleration??

I am afraid this does not make sense to me.

Could you please attempt to explain this to me Alan?

-------------------------------

Once the slider is at the top, it is then moved back down again.  Was this meant to be considered in this problem.  I thought it was and that completely threw me because I don't know what force it returns with.  Maybe gravity ??

Maybe I was not suppose to consider the downward motion??

-------------------------------

That makes sense - thanks Alan.    

Thanks very much Alan.  

Alan, I just drew these graphs.  I think that they are ok but could you check them please.

Unfortunately the pictures do not seem to be displaying properly tonight.  Oh well maybe it will appear properly tomorrow.  

Here is an online version.  It is the same.