4x^2-x=0
Please note: If the question was not so specific you would never so this one this way!
$$\\4x^2-x=0\\\\
x^2-\frac{1}{4}x=0\\\\
x^2-\frac{1}{4}x+(\frac{1}{2}\times\frac{1}{4})^2=0+(\frac{1}{2}\times\frac{1}{4})^2\\\\
x^2-\frac{1}{4}x+(\frac{1}{8})^2=0+(\frac{1}{8})^2\\\\
x^2-\frac{1}{4}x+\frac{1}{64}=\frac{1}{64}\\\\
x^2-\frac{1}{4}x+\frac{1}{64}=\frac{1}{64}\\\\
(x-\frac{1}{8})^2=\frac{1}{64}\\\\
x-\frac{1}{8}=\pm\frac{1}{8}\\\\
x=\frac{1}{8}+\frac{1}{8}\qquad or \qquad x=-\frac{1}{8}+\frac{1}{8}\\\\
x=\frac{1}{4}\qquad or \qquad x=0 \\\\$$
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