Melody

$$\\\frac{3}{4}+\frac{x}{8}=1\\\\
\frac{x}{8}=1-\frac{3}{4}\\\\
\frac{x}{8}=\frac{1}{4}\\\\
x=\frac{1}{4}\times 8\\\\
x=2$$

You cannot solve this because there are 2 variables.  You need 2 equations to solve for 2 variables.  

 (X-Y) (X-Y) =X^2-2XY+Y^2

Is that what you are feeling like today anon?    :(

$$\begin{array}{rll}
\frac{5n}{2}&=&\frac{8}{(3n-24)}\\\\
2(3n-24)\times\frac{5n}{2}&=&\frac{8}{(3n-24)}\times2 (3n-24)\\\\
(3n-24)\times5n&=&8\times2\\\\
15n^2-120n&=&16\\\\
15n^2-120n-16&=&0\\\\


\end{array}$$

$${\sqrt{{{\mathtt{120}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{16}}}} = {\sqrt{\left({\mathtt{16}}{\mathtt{\,\times\,}}{\mathtt{4}}{\mathtt{\,\times\,}}\left({{\mathtt{15}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}}\right)\right)}} = {\mathtt{8}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{240}}}} = {\mathtt{16}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{60}}}} = {\mathtt{32}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{15}}}}$$

$$\\n=\frac{120\pm32\sqrt{15}}{30}\\\\
n=\frac{60\pm16\sqrt{15}}{15}\\\\$$

35/100*x=70

multiply both sides by 100/35

(100/35)*(35/100)x=70*100/35

x=200

some of your question is missing - I might be able to fill in the dots :)

y=mx+c

52 = -1.75(32) + c

52 = -56 + c

add 56 to both sides and you get

52+56=c

c=108

y=-1.75x+108

here is your graph

Thanks Gino for looking after those :)

@@ End of Day Wrap    Wed 12/11/14      Sydney,   Australia       Time 3:35 pm             ♬

Hi everyone,

We were on a roll today.  Lots of questions and answers but we got through them all so I am writing the wrap early today :)))    Oh, Rosala returned to - that is great :))))) 

Great answers from Kaepernicks, xXFareXx, CPhill, reinout-g, geno3141, SevenUp, Kitty<3, Anonymous4338, Phanolo, Hc2027, justinas, happy7 and Rosala.  Lots of helpers today.  That is great. Thanks everyone.  

Now for a few interest posts:

1) Rosala's back  Hip Hip Horray!

any real number divided by itself = 1  (except for 0)