Melody

inverse sine is the same as arc sine so on the calc on the home page just type in

asin(14/16) and press equals  

Sasflower, you forget the negative sign.  But otherwise it was a great answer :))

I am really impressed by your logic JonesDaBoi  

I thought I might just try to do it by conventional algebra.

$$\\Find\;\; 2C+3T\\
6C+3T=4800 \rightarrow \;2C+1T=1600 \rightarrow \;2C=1600-1T \;\;(1)\\
8C+1T=4600 \rightarrow 1T=4600-8C \;\;(2)\\
$sub $ (2)\;\; into\;\;(1)\\
2C=1600-(4600-8C)\\
2C=1600-4600+8C\\
-6C=-3000\\
C=500\\
2C=1000\\
$sub back into (1)$\\
1000=1600-1T\\
1T=600\\
3T=1800\\
2C+3T=1000+1800=2800$$

so 2 cars and 3 Trucks are $2800

you know JonesDaBoi I like your solution better.   If I could give you more points I would  

-2x+17 cannot be simplified  

((1 +3/20)*2)+(1+ 7/20)

just add the red bits and do it straight on the calc on the home pages 

continuing irmjj's answer

If two pooints on the line are     $$(x_1,y_1)\;\;and\;\;(x_2,y_2)$$

$$slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}$$

great answer irmjj  

no happy - a light year is a distance not a time. :)

It will take 65 years.      Just like CPhill said.  :)

It is not 0 happy - it is just a very little number  :)

2.9979x10^8 * 6.626x10^-34

=2.9979* 6.626x10^(8 -34)

=2.9979* 6.626*10^(-26)

$${\mathtt{2.997\: \!9}}{\mathtt{\,\times\,}}{\mathtt{6.626}} = {\mathtt{19.864\: \!085\: \!4}}$$

=19.8640854 x 10^-26

=1.98640854 x 10^-25

I think that the intended question is 

(4.414x10^(-21)) / (1.60x10^(-19))

$${\frac{\left({\mathtt{4.414}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{21}}\right)}\right)}{\left({\mathtt{1.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{19}}\right)}\right)}} = {\mathtt{0.027\: \!587\: \!5}}$$