Melody

As far as notation goes I think that this is what you are after?

$$P(A)=\displaystyle \lim_{i=1}^X}\;\;\frac{^{n{_i}}C_{k_i}}{^nC_k}$$

this is written in LaTex. I opened the LaTex formula button and typed in

P(A)=\displaystyle \lim_{i=1}^X}\;\;\frac{^{n{_i}}C_{k_i}}{^nC_k}

This is all too much for me at the moment but I would try using known quatities of things.

If I could work out what to do for the known quatities then I would extrapolate to get a formula for the unknown quanities.

I am not saying it will necessarily work but that is how I would try to attack the problem.   

good luck    

You can get the anser to that from any calculator.

NO !!!!!

YOU CAN ONLY FIND THE ARC SINE OR ARC COS (INVERSE SINE OR INVERSE COS)

OF NUMBERS (RATIOS) BETWEEN -1 AND 1 INCLUSIVE  

Try watching this video

NO

think about it.

In a right angled triangle  cos= adjacent / hypotenuse

the hypotenuse is the longest side so this fraction must be less than 1

When dealing with angles that are not acute

$$-1\le cos\theta\le1$$

Not much since it is virtual.

$$\\\cos180^0=-1\\\\
\int\;cosx\;dx=\;sin(x)+c\\\\$$

Look through this post