Good answer anon although not many calcs do base three so you cannot just plug the numbers in and get an answer. 
I am going to write the question sightly differently
$$\\If\;\;\;y=log_{\textcolor[rgb]{0,1,0}3}3^6\\
then\\
3^6=\textcolor[rgb]{0,1,0}{3}^y\\\\
$Now it is very easy to see that y=6$\\
$so$\\
log_33^6=6\\\\\\
$Remember: $\quad \boxed{If \quad y=log_ba\quad then \quad a=b^y}\\\\
$ You say this as \qquad y=log a base b$\\\\
$Also remember : $\boxed{\mbox{A log is a power}}$$
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