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scrutinizer
यूजर का नाम
scrutinizer
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+259
How to convert Mbps in MBps
Hi, I wanted to use the sci calc, but don't know how the command line should look like for converting data speed of 9.98 Mbps in MBps. Could you give me an advise?
Thanks
Melody
●
scrutinizer
30 Nov 2014
#1
+259
0
Do you mean "acceptance region" (of argument)? If you do, then it's
from -infinity to +infinity
(the acceptance region of linear function)
scrutinizer
30 Agu 2013
#1
+259
0
-5(1-5x)+5(-8x-2)=-4x-8x => 5(-8x - 2 -(1 - 5x))=-12x => 5(-8x - 2 -1 + 5x)=-12x => 5(-3x - 3))=-12x => 5*(-3)(x +1)=-12x
, dividing both sides by -3, we get
5(x + 1) = 4x => 5x - 4x = -5 => x = -5
[input]solve(-5(1-5x)+5(-8x-2)=-4x-8x,x)[/input]
scrutinizer
30 Agu 2013
#1
+259
0
Once again, if you need
to solve
something there
must
be equality sign!
scrutinizer
30 Agu 2013
#1
+259
0
-1|3x-2|=7. |3x-2| is the absolute value. Breaking free of the parentheses it looks either as (3x - 2) if 3x - 2 > 0 and the equation is -1(3x-2)=7 or (2 - 3x) = -(3x - 2) if 3x - 2 < 0,and the equation would look as -1(2-3x)=7. Hence you have two equations in one that is due to the fact that the absolute value can hide both negative and positive values of the same number or expression.
scrutinizer
29 Agu 2013
#1
+259
0
Did you mean
"to express t in the terms of other variables"
?
If yes, then
m + 1 = e^lambda*t => lambda*t = ln(m + 1) => t = ln(m + 1)/lambda
Does t is part of the power?
[input]m= e^lambda*t -1[/input]
scrutinizer
29 Agu 2013
#3
+259
0
Hmm, then I myself have to think properly.
scrutinizer
29 Agu 2013
#1
+259
0
4x^2 - 2x where X = 2 is identical to 4*(2^2) - 2*2 = 4*4 - 4 = 12
scrutinizer
29 Agu 2013
#1
+259
0
Just incert the guven numbers into the equation. Or what sort of the expression this one belongs to - equation, one, needed to be simplified or smth else? If this is an equation it has to be equaled to something (number or expression)
scrutinizer
29 Agu 2013
#1
+259
0
depends on the sign between numbers 30 and 4x and on the value of x
scrutinizer
28 Agu 2013
#1
+259
0
e
is the base of natural logarithms,a transcendental number. http://en.wikipedia.org/wiki/E_%28mathematical_constant%29
scrutinizer
28 Agu 2013
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