scrutinizer

1 Questions
125 Answers

0

1036

1

+259

How to convert Mbps in MBps

Hi, I wanted to use the sci calc, but don't know how the command line should look like for converting data speed of 9.98 Mbps in MBps. Could you give me an advise?

Thanks

scrutinizer 30 Nov 2014

+259

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0.05 * 2800 or (5*2800)/100

scrutinizer6 Sep 2013

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A/q - 1 = wk => w = (A/q - 1)/k

scrutinizer5 Sep 2013

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x^4-20x^2+64 = 0, y = x^2 => y^2 - 20y + 64 = 0 => y1 = 16, y2 = 4 --> x^2 = 16 --> x = +-4. x^2 = 4 --> x = +-2

solve(x^4-20x^2+64 = 0, x)

scrutinizer5 Sep 2013

+259

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[input]solve(x^7=2,x)[/input]

[input]sqrt(2,7)[/input]

scrutinizer5 Sep 2013

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Depends on the measurement of the angle. For those that are multiples of the angles of 0,30,45,60,90 degrees there are commonly accepted values that are to be memorized much like times table is. For other angles, if you need an exact value, you can look into table of values for the trigonometric functions. However, there a sort of tasks exists where a value is required to be found on your own without the use of tables and calculators. Tan of what an angle exactly do you need to find?

scrutinizer5 Sep 2013

+259

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Rather, it would transpher the graph 3 points up Y-direction

scrutinizer5 Sep 2013

+259

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4/3+3m/5=41/15. Note that the both items of the left side can be reduced to the common denominator 15. (20 + 9m)/15 = 41/15. Breaking free of the denominator by multiplying both sides by 15 we get 20 + 9m = 41 => 9m = 21 =>m = 21/9 = 7/3

[input]solve(4/3+3*m/5=41/15, m)[/input]

scrutinizer3 Sep 2013

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There were 360 rails of 8 meters length removed, all in all 360*8 = 2880 meters of removed rail sections. 2880/12 = 240 rails sections of 12 meters length each you need to place instead of old ones.

scrutinizer3 Sep 2013

+259

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3(1/2)^4-2(1/2)^4+5(1/2)^2-4(1/2)+1 = (1/2)^4 + (1/2)(5*1/2 - 4) + 1 = (1/2)((1/2)^3 + 5*1/2 - 4) + 1 = (1/2)(1/8 - 3/2) + 1 = -(1/2)*(11/8) + 1 = 1 - 11/16 = 5/16

3(1/2)^4-2(1/2)^4+5(1/2)^2-4(1/2)+1

scrutinizer3 Sep 2013

+259

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"Give the slope and the y intercept of the line" by what object, not clear? The slope can be determined if you express y: 3 x + 10 y = 5 => 10y = 5 - 3x => y = [5 - 3x]/10 =>

y = -0.3x + 0.5. arctan (-0.3) = -arctan (0.3)

[input]-atan(0.3)[/input]

Well, as is unclear your question about what by what is intercepted as it is, let's assume that the line intercepts Ox, we have to find x, i.e. let's assume that there such point A exists that the graph is inter-crossing Ox at the point A (x ; 0). Inserting 0 instead of y, we'll get 0 = -0.3x + 0.5 => 0.3x = 0.5 => x = 0.5/0.3 = 5/3. If we wish to find the coordinate y of the graph inter-crossing Oy, then we assume that there such point B exits, that B (0 ; y) => y = -0.3*0 + 0.5 = 0.5. Did I answer your question?

The graph is below

[input]plot(-0.3x + 0.5, x=-5..5, -5..5)[/input]

scrutinizer2 Sep 2013