scrutinizer

1 Questions
125 Answers

0

1036

1

+259

How to convert Mbps in MBps

Hi, I wanted to use the sci calc, but don't know how the command line should look like for converting data speed of 9.98 Mbps in MBps. Could you give me an advise?

Thanks

scrutinizer 30 Nov 2014

+259

0

9 = 3*3, 15 = 3*5. 9 consists of 2 numbers 3, 15 contains one number 3. Hence the common lower multiple is 3.

scrutinizer20 Sep 2013

+259

0

d means "differentiation operator". If you tell this to you teacher he will be agreeably surprised, assure you.

scrutinizer18 Sep 2013

+259

0

x-o.2x+o.o7(x-0.2x)=73.53 => (x - 0.2x)(1 + 0.07) = 73.53 => (x - 0.2x)*1.07 = 73.53 => 0.8x*1.07 = 73.53 => 0.856x = 73.53 => 856x = 73530 => x = 36765/428

solve(x-(0.2x)+0.07(x-(0.2x))=73.53,x)

scrutinizer13 Sep 2013

+259

0

log ab^2 = log(b^2, a) = 2log(b,a) = 2log(7,3)

scrutinizer12 Sep 2013

+259

0

scrutinizer12 Sep 2013

+259

0

However, there's another way to solve this equation using 2 Bezout theorems about roots of polynomial. According to the 1st one, the polynomial p(x) can be exactly divided by the binomial (x - a) if x = a and the quotient is p(a), and according to the 2nd one if the polynomial with the whole coefficients have roots that are the whole numbers then these roots are divisors of the polynom's constant term.

In this case we should apply the theorem 2 first and look for divisors of 6. They are -1,1;-2,2;-3,3;-6;6. Then we insert into the equation them to make sure whether one of them fits it. The suitable integer is 3. As the coeffs of the expression are the whole numbers the polynomial is being divided by the binomial x - 3 exactly, so its 1rst root is x = 3. To find the other roots we should divide the polynomial x^3-x^2-4x-6 by x - 3. Performing long division we get the quotient x^2 + 2x + 2, so the full arrangement will look as (x - 3)(x^2 + 2x + 2) = 0 The first factor has the root already had been calculated (x = 3). The second equation has no roots among the real numbers but has two roots among the complex numbers: x2 = -1+ i, x3 = -1 - i

solve(x^3-x^2-(4x)-6 = 0,x)

scrutinizer11 Sep 2013

+259

0

Strongly recommend to read this on how to solve cubic equations:

http://mathforcollege.com/nm/mws/gen/03nle/mws_gen_nle_bck_exactcubic.pdf

scrutinizer9 Sep 2013

+259

0

(2 sqrt50 - 3 sqrt8 )^2. First you could simplify the expression: (2 sqrt{25*2} -3 sqrt{4*2} )^2 = (2 *5 *sqrt{2} -3*2* sqrt{2} )^2 = (10sqrt{2} - 6* sqrt{2} )^2 = (4sqrt(2))^2 = 16*2 = 32

scrutinizer9 Sep 2013

+259

0

More detailed version: 2/3h-9=6-2/3h => 2 - 9*(3h) = 6*(3h) - 2 =>15*(3h) = 4 =>3h = 4/15 => h = 4/45

scrutinizer9 Sep 2013

+259

0

When something "lies between" it's always two objects (numbers) it lies in between. So, "between sqrt(26) and..."?

scrutinizer9 Sep 2013