Let's examine how we can arrive at Alan's answer, since it might not be immediately intuitive........
Note that log 3500 asks.........What power do we raise 10 to in order to obtain 3500 ???
By a property of logs, we can write
log 3500 as 500*log3 .........and evaluating this gives us......... 238.56062735983122
Now....note that the "whole number" part of this tells us what power (exponent) will be on the "10" in the scientific notation representation of 3500 , and 10 raised to the decimal part will tell us what some of the first few digits of that number will be (within a certain degree of accuracy).
So 10.56062735983122 = 3.63602917958700501 (Only the first 12 digits of this are accurate for 3500 ... see below)
Thus, in scientific notation we would have......
3.63602917958 X 10238
This number is actually 239 digits in length and Alan's answer of 3.636×10238 is good enough !!!!
However....if you insist.....we have
3636029179586993684238526707954331911802338502600162304034603583258060019158389548419850
8262979388783308179702534403855752855931517013066142992430916562025780021771247847643450
125342836565813209972590371590152578728008385990139795377610001
I think I'll stick with the scientific notation........