$g(2x) = \frac{2x + 3}{4}$
$2(g(x)) = 2 \frac{x+3}{4} = \frac{x+3}{2}$
$\frac{2x + 3}{4} = \frac{x+3}{2}$
$2x + 3 = 2(x+3)$
$2x + 3 = 2x + 6$
$3=6$
No solutions
$5 = -3m + b$
$-4 = 0m + b$
$b = -4$
$5 = -3m + (-4)$
$5 = -3m - 4$
$-3m = 9$
$m = -3$
$-4 + (-3) = \boxed{-7}$
$\frac{-12 + x_2}{2} = -20$
$\frac{13 + y_2}{2} = 14$
$-12 + x_2 = -40 \Rightarrow x_2 = -28$
$13 + y_2 = 28 \Rightarrow y_2 = 15$
$(x_2, y_2) = \boxed{(-28, 15)}$
What are even functions? Even coefficients? Only even exponents? Even constant?
(2) $c+d=81$
$f(1) = 3 + b + c + d = 3 + b + 81 = 84 + b.$ $b$ is at least $1$ so the answer is $84+1=\boxed{85}$
Use vietas and do it yourself, because, god, I am not going to do that.
No problem! Also, if you want LaTeX text, you can use the \text{} environment:
$$\text{Wow, this is clearer text!}$$
I think it is double dollar signs:
$$0$$
Hint: Multiply the equations by xyz.
A) No. B) No
BTW u play roblox or what
$2 \cdot 8 - \frac{8}{4} = 16 - 2 = \boxed{14}$
