MathProblemSolver101

x+3x+2x=180

6x=180

x=30

By the Chinese Remainder Theorem, we have $N \equiv 221 \pmod {315}$

The least such integer is $\boxed{221}$

Ugly problem with solutions. I tried and got a very complex radical expression. Are you sure the question is stated correctly?

$12-(9-2)+2=7$

$\frac{\binom{10}{2}}{\binom{20}{2}} \cdot \frac{\binom{10}{2}}{\binom{18}{2}}$

Feel like this is wrong ..

Hey guest,

Try forming cases, if n == {0, 1, 2, ... ,8} mod 9

log(ab)=2log(a-2b)

log(ab)=log((a-2b)^2)

ab=(a-2b)^2

solve for a/b

how the c**p did you get 150. the angles not even 75

Guest, your English is a bit off. I put this into a Grammarly document, and I got your question now! 

The question, is Grammarly is correct, is: How many ways are there to choose french fries and potatoes if there are 5 french fries and 2 potatoes?

Well, you can choose 0, 1, 2, 3, 4, 5, or 6 french fries. You can also pick 0, 1, or 2 potatoes.

The number of choices are $7 \cdot 3 = \boxed{21}$

\(\begin{align*} \binom{7}{3}\binom{6}{2} + \binom{7}{4}\binom{6}{1} + \binom{7}{5} &= 35 \cdot 15 + 35 \cdot 6 + 21 \\ &= 7 \cdot (75+30+3) \\ &= 7 \cdot 108 \\ &= \boxed{756} \end{align*}\)