MathProblemSolver101

Hello, LaTeX is rendered as an image and please make sure to type those fancy numbers out next time.

Question: 

A school offers both Spanish and Chinese language classes. This past week, 10 students dropped from the Chinese classes, which increased the number of students who take neither class from 27 to 31. How did this change impact the number of students who take the Spanish class but not the Chinese class?

A school offers both Spanish and Chinese language classes. This past week, 10 students dropped from the Chinese classes, which increased the number of students who take neither class from 27 to 31. How did this change impact the number of students who take the Spanish class but not the Chinese class?

31-27=4 people totally dropped out of both

10-4 = 6 people more who have dropped out of Chinese but still take Spanish.

(1,1) => 5*2 = 10

(2,2) => 5*(-6) = -30

(3,3) => 5*(-6) = -30

Nice, EP!

Your sarcasm and "no u" comment is not working because I did not copy. Thou art not worthy of speaking back with the same words, thus.

Nice, guest for copying this website!

https://thefractioncalculator.com/CompareFractions/is-3/8-less-than-5/6.html

Learn how to do easy math, Guest.

learn how to compare fractions. This is a fourth grade question

Very thoughtful post, guest! 2&3 looks good to me but I do not know what sec is.

Clay's dinosaur footprint is 3 times longer than Patrick's dinosaur footprint. It takes 18 paperclips to measure Clay's dinosaur footprint. How many fewer paperclips would it take to measure Patrick's dinosaur footprint?

C = Clays Dinosaur

P = Patricks Dinosaur 

We have c = 3p (1)

We also have c = 18 (2)

(1) = (2) => 3p = 18

p = 6 (3)

|(2)-(3)| = |18-6|=12 fewer

Haley paid $24 for a toy and a radio. The radio costs 3 times as much as the toy. What is the price difference between the two items?

Let r = radio

Let t = toy

We have r+t=24 (1)

We also have r = 3t (2)

(2) into (1) => 4t = 24

t=6 (3)

(3) into (2) => r = 18 (4)

|(4)-(3)| = |18-6| = 12 dollars

Used wolfram for the last part :P.

cis(pi/8) = sqrt(2 + sqrt(2))/2 + 1/2 i sqrt(2 - sqrt(2))

cis(pi/3) = -1/2 + (i sqrt(3))/2

3 \sqrt{3 * sqrt(2 + sqrt(2))/2 + 1/2 i sqrt(2 - sqrt(2))} * 3 \sqrt{5 * (-1/2 + (i sqrt(3))/2)} = 9 sqrt(5 (-1/2 + (i sqrt(3))/2)) sqrt((3 sqrt(2 + sqrt(2)))/2 + 1/2 i sqrt(2 - sqrt(2)))

$\sum_{n=1}^{33} \frac{1}{(3n-2)(3n+1)} = \frac{33}{100}$ because it has an asymptote that gets really close to $33.\overline{3}.$