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Melody

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यूजर का नामMelody
स्कोर118691
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WELCOME BACK CPHILL !


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Melody  11 Feb 2022
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So I assume that means that in a day or 2 you will stop answering questions for a few weeks but you intend to start up again when you get back.
Is that right? You might have a hard time finding this post. If you are a formal member it will be easy. It would just be under your posts. But I have a feeling that you haven't formally joined up so it might be harder. (just remember the date of your last post, that should make it easier.)
Thanks for letting me know. Have a great holiday. Do you live in Western Australia, Perth maybe?

That last question was brilliantly answered.

I'll give you another on like that:
--------------------------------------------------------------------------
I want you to copy this question and put the answers after each of my questions. So that the answers stay with the question.

Toni has some in an account
The interest rate is 6.8% per annum
Interest is compounded every 2 months
a) ( think about how many 'nets' of interest there are in a year.) How many times each year is the interest compouned ?
b) What is the 2monthly rate of interest? This is the interest per compounding period, don't forget to put r= ? You forgot the r= last time

If Toni leaves his money in the account for just 2 month then he has left it there for just 1 compounding period. so n=1
what will n be if [Note: Put n = every time ]
c) john leaves the money there for 4 months Ans: n=?
d) for 6 months Ans:
e) for 8 months Ans:
f) for 10 months Ans:
g) for 1 year Ans:
h) for 18 months Ans:
i) for 2 years Ans:
j) for 2 years and 2 months Ans:
g) for 3 years Ans:
(if you are starting to get confused by the big numbers, look back and see how we did it before - we used the number of compounding periods 'nets' in a year to help us.)
h) for 9 years Ans:
i) for 25 years Ans:
j) for 68 years Ans:
k) If Toni leaves his money in this account for 68 years and the bank doesn't change the account in any way, what will r be after 68 years? Please think
Please think about your answers and follow all my instructions.
10 Jan 2014