Melody

I do not remember hearing about  this number phi before about a week ago and since then it must have been mentioned half a dozen times.  I guess I should try to slot it into my memory bank somewhere.

Good luck there.   LOL  

Use the site calc on the home page.

Try this

"Take 2 tsp (10ml) olive oil and one (5ml) of apple vinegar mix with a little water. It will help "

A clever person once told me of this remedy for nausea - i do not know if it works.  :))

1^ any real number = 1

So  1^x=1

The integral of 1 is x+c

I think that is the answer 

$$\\log_5\;\sqrt{17}\\\\
=log_5\;17^{0.5}\\\\
=0.5\times log_5\;17\\\\
=0.5\times \frac{log17}{log5}\\\\$$

(I used the change of base law)

$${\frac{{\mathtt{0.5}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{17}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} = {\mathtt{0.880\: \!187\: \!213\: \!861\: \!293\: \!8}}$$

You cannot solve because there is no equal sign !

perhaps it is meant to equal zero?

If that is the case then you could use the quadratic formula to solve it :)

There is an error in your question.

You have 2 equal signs in your second equation.  

Nauseated - are you being nausiating AGAIN!     

I wonder if there is an inoculation WE can get to protect us from your affliction?

BUT you are right CPhill does not make many mistakes and hopefully I don't either  LOL

It is good that TayJay questioned CPhill's answer.  Maybe the wording could have been a bit more tactful, but the important thing is that TayJay learned and this would not have happened if he/she did not comment on what was thought  to be an incorrect answer.

$$\begin{array}{rll}
y&=&x^2+5x+4\\
y-4&=&x^2+5x\\
y-4+(5/2)^2&=&x^2+5x+(5/2)^2\\
y-4+25/4&=&x^2+5x+25/4\\
y+2.25&=&(x+5/2)^2\\
(x+2.5)^2&=&y+2.25\\
\end{array}\\\\
vertex\;\;(-2.5,-2.25)$$

I like that one anon I haven't heard either before.  I am from down under you know!  LOL