Nirvana

You got it EP! :D 

here's more hints though....

please remember the rules of the transformation of functions.......
I'm not going to use your exact problem but let's do something similar: 

pretend I gave you parent function ⇒ \(f(x)= x^2\)

what do we know about this? 

well we know that it is a parabola! 
so lets say i then give you function g(x)
\(g(x)= (x-3)^2 +4\)

what can you tell me about this?? 

well remember that \(f(x)=(x-h) \) shifts your function h units TO THE RIGHT!! 
and \(f(x)= (x+h) \) shifts it h units TO THE LEFT!! 
and..... finally....
\(f(x)=x+k\)  your function MUST be shifted k units UP! and if k was negative it would be k units DOWN!

now apply this rule to your problem and see if you understand it.........

hope this helped in some way !

what do you mean by simplify?? 
are you trying to solve for x? 
are you trying to simplify your expression?

please give me more details so i can further assist you 

lol me on every test 

there's not a name for that specific thing, (it looks awesome btw) 

but theres something sort of similar 

pretend you are given a line segment and you are told to construct the perpendicular bisector 

what you'd do is to take your "compass" and make a bunch of concentric circles about 2/3 of the way past your mid point (on the line segment) 

and you would want to do this on both sides so from one end point to the other (and remember to keep compass setting the same!) 

and so these "concentric circles" wherever they intersect, you can draw a line from the top to the bottom and there you have your perp. bisector....

again, it's not the same it just kind of reminded me of that :') 

excuse my trash grammar btw im really braindead and tired :')

like they established already that 6000 comes from the 1200 students with the total of 5 classes among them....

soo,,,,,, and we originally know that in EACH class there is a total of 30 students so...... in order to find the ACTUAL number of classes 

 you had to take that 6000 and divide it by 30 bc you know that you have 6000 students and you also know that each class has thirty so...
 

30x = 6,000

think of it like that :D 



 

i think this is awesome! 

idrk what the AMC8 might have on it...since i haven't done the AMC's in like a thousand years :') 
but what i can tell you is that you should look at the past year's problems or do some problems on like AOPS or something just to warm up your brain for tomorrow! :D 

you will do awesome don't worry 

LOL ok i was gonna do it but now im scared

that is exactly what  i wanna hear :D good job learning and understanding the material :)