Hello Guest!
what is the required angle for the tan(-1/4)?
The required angle for the tan(-1/4) is arctan(-1/4) = -14.0362°
Greeting asinus :- ) !
Hallo Gast!
Hallo, was ist der Unterschied von:
x+x+x= ist das 3x
x*x*x= ist das x Hoch 3 ⇒ x3
2*2*2 = ist das 2 Hoch3 ⇒ x3
Ja, du hast recht. Alles ist richtig!
Weiterhin viel Spaß und Erfolg in der Schule wünscht dir
asinus :- )
!
Guten Abend Sandra!
Berechne die Variablen!
6 : y : 8 = 15 : 5 : (z + 3)
Ich zerlege in drei Verhältnisgleichungen.
Danach : Außenglied mal Außenglied gleich Innenglied mal Innenglied.
1.
6 : y = 1 5 : 5
15y = 30
y = 2
2.
6 : 8 = 15 : (z + 3)
6z + 18 = 120
6z = 102
z = 17
3. (Zur Probe)
y : 8 = 5 : (z + 3)
y * (z + 3) = 40
2 * (17 + 3) = 40 was richtig ist.
Hoffentlich konnte ich dir helfen.
Gruß und gute Nacht!
https://www.youtube.com/watch?v=FccpfM-P4vY
Hello SaoFeng!
how many times will four over five go into 6
Wie oft geht vier über fünf in 6 ?
6 / 54 = 6 / 625 = 0.0096
Greeting asinus :- )
9 7/10 rounded to the nearest half?
9. 7/10 ≈ 9.5
Was that what you meant?
What percent is 1000 from 2 200 000?
x = 1 000 * 100% / 2 200 000
Hello DamienDenninson!
An jet flies between two points on the ground that are 500 km apart with an airspeed of 200 m/s. The destination is directly north of the point of origin of the flight.. If a constant wind blows at 10 m/s toward the west during the flight, what direction must the plane fly relative to the air to arrive at the destination?
A.5.9° east of north
B.2.9° east of north
C.2.9° west of north
D.5.9° west of north
E.85° west of north
sin α = ( t * 10 m/s) / (t * 200 m/s)
sin α = 10 / 200 = 0.05
α = arcsin 0.05
Answer B is correct.
The heading of the aircraft is
α = 2.866° east of north
Hallo Guest!
(1/1000)(-1/3)
(1/1000)(-1/3) = (10-3)(-1/3) = 101 = 10
(1/1000)(-1/3) = 10
81(-3/2)*(-1/2)
81(-3/2)*(-1/2) = 34*(-3/2)*(-1/2) = 33
(81(-3/2) (-1/2) = 27
O.K.
Gruß asinus :- )
!
