CPhill

In exponential form, this says that

10^^-.123 = 0.753 = x

-2.6*-5.5 =

14.3

I assume this might be.....(4/5)*(10x+4)-8x+(5/2)...if so, we have

8x + (16/5) - 8x + (5/2) =

(16/5) + (5/2)  =

[16(2) + 5(5)] / 10 =

[32 + 25] / 10 =

57 / 10  =

5 + 7/10

|6 + z | - |-7|  =

l6 + z l - 7

Notice, that if z ≥ -6, then the answer is

6 + z - 7    =

z - 1

But, if z < -6, then the answer is

- z - 13

So we have .7777.......

= 7/9

Let x be the original cost of one computer and y be the original cost of one printer.

So, the first equation is

3x + 1y = 1800

And when the price of a computer fell by  $500 we have....

2(x-500) + 2y = 1300     → 2x - 1000 + 2y = 1300→ 2x + 2y = 2300

So we have 2 equations

3x + 1y = 1800

2x + 2y = 2300

Multiplying the first equation by -2 on both sides, we have

-6x - 2y = -3600

2x + 2y =   2300

And adding them together, we have

-4x = -1300

Then the original cost of the computer was $325

And Melody's answer is correct !!! [This problem probably needs some "tweaking" so that the answer is  a "real-life" quantity...!!!]

(A*b*c)^4*3/(b*c)^3*b^3/27a^5    So we have, taking it in steps.......

[A⁴b⁴c⁴]*[3] /[b³c³] = 3[A⁴bc]

3[A⁴bc]*[b³] = 3[A⁴b⁴c]

3[A⁴b⁴c] / [27a⁵ ] =

[A⁴b⁴c] / [9a⁵ ]

(5 + 5677643628300219/10,000,000,000,000,000) i

Very impressive, guys....!!!!

Very nice, Melody.......