We have a problem here......we can't have a polynomial with only one complex root....all complex roots to a polymomial occur in pairs. Specifically, in your polynomial, the other complex root would be 2 + 3i.
I'll construct one with all these roots, and you can take your chances. So we have....
(x + 1)(x + 1)(x -(2-3i))(x - (2 + 3i))
This gets a little messy, so hang on...multiplying the first two terms together, we get x^2 + 2x + 1
Let's set this aside for the moment and concentrate on the last two .... so we have
(x -(2-3i))(x - (2 + 3i)) = (x^2 -x (2 - 3 i) - x (2 + 3i) + (2-3i)(2+3i) =
(x^2 -2x +3xi -2x -3xi + 4 -6i + 6i - 9(i)^2) = (x^2 - 4x + 4 + 9) = (x^2 - 4x + 13)
Now, putting the two together, we have
(x^2 + 2x + 1) (x^2 - 4x +13) =
x^4 + 2x^3 + x^2 - 4x^3 - 8x^2 - 4x + 13x^2 +26x + 13 =
x^4 -2x^3 + 6x^2 + 22x + 13 = P(x)
See...I told you it could get messy....!!
BTW...I checked this one with a solver and it was correct.......