asinus

x hoch zwei = 15x

${\color{blue}x^2=15x}$

${\color{blue}x^2-15x = 0}$           $[\ x \ \ ausklammern!$

${\color{blue}x\times(x-15)=0}$

Es ist ein Produkt aus zwei Faktoren, das 0 werden soll. Ein Produkt ist genau dann 0, wenn mindestens ein Faktor 0 ist. Man kann daraus schließen, daß mindestens ein Faktor 0 sein muß. Es gibt zwei Möglichkeiten:

  1. x = 0

  2. Klammer ist 0:   x - 15 = 0  ⇐⇒  x = 15
 

Offensichtlich hat die Gleichung also zwei Lösungen:

x₁ = 0       x₂ = 15

asinus :- )    !

Find all the values of theta between 0 degrees and 360 degrees for sec theta=1

${\color{blue}sec\ \theta (\theta \in\{0°;360°\}) = 1}$ 

!

Use a calculator to find the natural​ logarithm, base
e.
ln 0.44

web2.0calc ⇒

Cursor to "log"
Below, "ln"                !  

Hello guest!

At t = 0 a ball is thrown straight upward from ground level at speed v0. At the same instant, a distance D above, a ball is thrown straight downward, also at speed v0.Where do the b***s collide (in terms of only D, v0, and g)?

Tonight came a new realization:
The b***s meet twice!

H = D - v₀t - (g/2)t²

(g/2)t² + v₀t + H - D = 0

  a          b         c

$t = {-b \pm \sqrt{b^2-4ac} \over 2a}$

$t = {-v \pm \sqrt{v^2-2g(H-D)} \over g}$

H =  v_ot - (g/2)t²

(g/2)t² - vt + H = 0

   a        b     c

$t = {-b \pm \sqrt{b^2-4ac} \over 2a}$

$t = {v \pm \sqrt{v^2-2gH} \over g}$

${\color{blue} {-v \pm \sqrt{v^2-2g(H-D)} \over g}}$= ${\color{blue}\frac { v \pm \sqrt{v^2-2gH}}{ g}}$ 

2v${\color{blue}\pm \sqrt{v^2-2gH}}$ = ${\color{blue}\pm\sqrt{v^2-2gH+2gD}}$

H must be calculated from this.
Maybe someone can help me.
For given sizes, the thing would be simple.

Greetings asinus :- )  !

Greeting asinus :- )   !

Hello guest!

At t = 0 a ball is thrown straight upward from ground level at speed v0. At the same instant, a distance D above, a ball is thrown straight downward, also at speed v0.Where do the b***s collide (in terms of only D, v0, and g)?

H = D - v₀t - (g/2)t²

H =  v_ot - (g/2)t²

D - v₀t - (g/2)t² = v_ot - (g/2)t² 

2v₀t = D

t = D / 2v_o

The b***s meet after the time t = D / 2v₀ . *

H = v_ot - (g/2)t²  = D/2 - (g/2) * D² / 4v₀²

H = D/2 - gD²  / 8v₀²

The b***s meet at height H = D/2 - gD²  / 8v₀² .*

Greeting asinus :- )   !

* b***s means Bälle.

what is the fraction?

34.53/175.90

${\color{blue}\frac{34.53}{175.90}=0.19630471859}$  !

what is (-3) squared

${\color{black} Minus \ times \ minus \ equal \ plus.}$

${\color{blue}(-3)^2=(-3)\times(-3) = 9}$   !

1\2 × -1\3

${\color{blue}\frac{1}{2}\times(-\frac{1}{3})=-\frac{1}{6}}$     !

8 divided by 2/3

${\color{blue}8:\frac{2}{3}= 8\times\frac{3}{2}=\frac{24}{2}=12}$   !

What is 5,000,000+6,789,654=

${\color{blue}5,000,000+6,789,654=11,789,654}$  !