Hello Guest!
a solid pyramid of height 40 cm with a square base of sides 30 cm each is put into a cubicle tank of sides 40 cm each. the tank is then filled with water. If the pyramid is removed, find the depth of water in the tank.
VTank = 403cm3=64000cm3
VPy = 13×302cm2×40cm=12000cm3
VRest = VTank - VPy = 64000cm3−12000cm3=52000cm3
h = VRest / ATank = 52000cm3402cm2=32,5cm
After removing the pyramid from the tank,
the water is 32.5cm high in the tank.
Greeting asinus :- )
!